|
Main Menu
Who's Online
There are 243 unlogged users and 0 registered users online.
You can log-in or register for a user account here.
Sponsored Links
|
Monday, February 10, 2003 - 02:27 PM
Here are three math tricks that involve your age. One of them allows you to find out someone's age even if they won't tell you.Trick #1
My wife taught me this one:
Watch this: 28 (age) x 7 = 196. 196 x 1443 = 282828! Actually, what you're doing is multiplying your age by 10101. Your age will repeat 4 times if you multiply it by 1010101. Notice the number of ones? Yep, four, hence four age repetitions. What if you're age 9 and younger? Does this still work? Well....sort of. You get 90909, or really, 090909. To really enjoy this, though, it helps to be 10 and older. Sorry kids. Trick #2
You should now have a number, the first digit(s) being your original number and the last two your age! Trick #3 Here's a sneaky way to find out someone's age who won't tell you:
This is one is a slight variation of Trick #1. Still fun to do, though.
The reason this trick works because 10101 is equal to 3367*3. And multiplying any two-digit number by 10101 is the same as writing it three times (e.g. 282828). Thus, when a number is multiplied by 3367, then by 3, it is really being multiplied by 10101. And of course, when you divide it by 10101 at the end of the trick, you get your original number, in this case your age.
If you like CuriousMath.com, here's a book you'll love: Learn more about More Rapid Math Tricks and Tips : 30 Days to Number Mastery
|
User's Login
Sponsored Links
Other Stories
|
Comments
trick # 3 does not work for all ages, should the step "Have the person add the second number of his or her age to the figure" be left out, here would be the results(they should still tell their result):
with the extra step: 15 x 5 = 75;
75 + 3 = 78;
78 x 2 = 156;
156 + 5 = 161;
deduct 6, can't do it because 1 is not equal to 6
without extra step : 15 x 5 = 75;
75 + 3 = 78;
78 x 2 = 156;
deduct 6 = 15
this whole thing works with numbers that end in zero: 10 x 5 = 50;
50 + 3 = 53;
53 x 2 = 106;
second digit of age: 106 + 0 = 106;
deduct 6 = 10
or even without it: 10 x 5 = 50;
50 + 3 = 53;
53 x 2 = 106;
deduct 6 = 10
or maybe i am misunderstanding something???
I think you misunderstood step 1 -- multiply the FIRST DIGIT of the person's age. You multiplied 15 by 5. If the person's age is 15, you multiply 1 by 5 (ie, the first digit), not 15. Try that and it should all make sense.
I really like tirck #1. How your age comes out to three.
55
110
115
5750
3997
2008
first, i started with 55, second i am not 8. whats wrong?
it was a reply for the trick 2, i accidently pressed the reply to instead.
trick 2 is correct,
(u made a mistake!)
55
110
115
5750
1754 (where did u get 3997 from?)
7504
1980
5524=55 original no,+24 age(correct!)
yeah actually you are... you should read a little better: It says multiply the FIRST digit of your age by 5, not the whole age
age: x y as in x and y digits.
2(x5+3) +y = 10x +y +6. x is shifted by 10 to be in the right base10. then just remove the offset of 6.
What's interesting is that if you mess up on the first step and multiply the entire number by 5, you just have to add a step at the end of dropping the ones digit and it will still work.
Only logged in users are allowed to comment. register/log in