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Monday, February 10, 2003 - 03:37 PM

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Tricks, Rules & MethodsHow can you quickly know if one number will divide evenly into another number, leaving no remainder? For example, will 3 divide evenly into 2,169,252? Well, I wouldn't have brought the subject up if I didn't know some curious shortcuts...
Division by 2
No surprise here. Any number that ends in 0,2,4,6 or 8 is evenly divisible by 2.

Division by 3
Add the number's digits. If the sum is evenly divisible by 3, then so is the number. So, will 3 divide evenly into 2,169,252? Yes it will, because the sum of the digits is 27, and 27 is divisble by 3. If you want, you can keep adding numbers until one digit remains. For example, keep going with 27. 2 + 7 = 9, which is also evenly divisible by 3.

Division by 4
If the number's last 2 digits are 00 or if they form a 2-digit number evenly divisible by 4, then number itself is divisible by 4. How about 56,789,000,000? Last 2 digits are 00, so it's divisible by 4. Try 786,565,544. Last 2 digits, 44, are divisible by 4 so, yes, the whole number is divisible by 4.

Division by 5
Any number that ends in a 0 or 5 is evenly divisible by 5. Easy enough.

Division by 6
The number has to be even. If it's not, forget it. Otherwise, add up the digits and see if the sum is evenly divisible by 3. It it is, the number is evenly divisible by 6. Try 108,273,288. The digits sum to 39 which divides evenly into 13 by 3, so the number is evenly divisible by 6. If you want, you can keep adding numbers until only one digit remains and do the same thing. So in this case, 3 + 9 = 12 and 1 + 2 = 3, and 3 is evenly divisible by 3!

Division by 7
Multiply the last digit by 2. Subtract this answer from the remaining digits. Is this number evenly divisible by 7? If it is, then your original number is evenly divisible by 7. Try 364. 4, the last digit, multiplied by 2 = 8. 36, the remaining digits, minus 8 = 28. The last time I checked, 28 is evenly divisble by 7, and thus, so is 364!

Division by 8
If the number's last 3 digits are 000 or if they form a 3-digit number evenly divisible by 8, then the number itself is divisible by 8. How about 56,789,000,000? Last 3 digits are 000, so it's divisible by 8. Try 786,565,120. The last 3 digits, 120, divide by 8 into 15, so yes, the whole number is divisible by 8.

Division by 9
Sum the number's digits. If it divides by 9, you're in luck. As with the tests for 3 and 6, you can keep adding numbers until you're left with only one digit.

Division by 10
Any number that ends in 0 is evenly divisible by 10.

Division by 11
Here are four ways for different types of numbers:
  1. If the sum of every other digit, starting with the first, is equal to the sum of every other digit starting with the second, then the number is evenly divisible by 11. Try 13057. 1+0+7 = 3+5, therefore it should divide evenly by 11. And indeed it does: 13057 / 11 = 1187.
  2. If all the digits are the same and there's an even number of digits, then the number is evenly divisible by 11. 333,333 - Yes. 3,333,333 - No.
  3. If the number is a 3 digit number with different digits, add the two outside digits. If the difference between the sum and the middle digit is 11 then 11 divides evenly into the 3 digit number. If the sum is the same as the middle digit, then 11 will also divide evenly into the number. Try 484. 4 + 4 = 8 which equals the middle digit so 11 divides into 484 evenly. How about 913? 9 + 3 = 12 and 12 - 1 = 11 so 913 is evenly divisible by 11.
  4. If the digits are different, count 'em from the right and then add the numbers in the odd positions and the even positions. Subtract the smaller number from the larger. If the difference is evenly divisible by 11, so is your original number. Take the number 181,907. The numbers 8,9, and 7 are in the odd positions. They sum to 24. The numbers 1,1, and 0 are in the even positions. They sum to 2. Subtract 2 from 24 to get 22. 22 divides by 11 into 2, so 181,907 is evenly divisible by 11.
Division by 12
If the number can be evenly divided by 3 and 4, the same can also be said for 12. Use the methods for Division by 3 and Division by 4 above. If they both work, your number is also evenly divisible by 12.

Division by 15
If the number can be evenly divided by 3 and 5, the same can also be said for 15. Use the methods for Division by 3 and Division by 5 above. If they both work, your number is also evenly divisible by 15.

Division by 24
If the number can be evenly divided by 3 and 8, the same can also be said for 24. Use the methods for Division by 3 and Division by 8 above. If they both work, your number is also evenly divisible by 24.

Division by 33
If the number can be evenly divided by 3 and 11, the same can also be said for 33. Use the methods for Division by 3 and Division by 11 above. If they both work, your number is also evenly divisible by 33.

Division by 36
If the number can be evenly divided by 4 and 9, the same can also be said for 36. Use the methods for Division by 4 and Division by 9 above. If they both work, your number is also evenly divisible by 36.


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Re: Divisibility Tricks
by RenKaftan
on Jan 31, 2004
I haven't checked all of them, but on numbers divisable by 6, that rule is not always true. For example. 1521893670 adds up to 42 which adds to 6 which is divisable by 3 and it is also divisable by 6. However, 1521893673 adds up to 45, which adds up to 9 which is divisable by 3 but not by 6.

As far as I know the rest work so thanks for the good info! :-)

-Ren

Re: Divisibility Tricks
by nzbruce
on Apr 29, 2004
Divisibility by 3 (and 9) rules work because of some nice algebra. I'll try to use the least number of technical terms so that children reading the site can follow it too.
If you take a three digit number, abc, then the number is made of of 100 lots of a, 10 of b and a single c.
We split up the 100 lots of a into 99 lots of a and one single a, we split the 10 lots of b into 9 lots of b and a single b.
We can split the 99 lots of a into 3 groups (33a's each) and we can split the 9 lots of b into 3 groups (3bs each).
So, if the sum of the single a, b and c values can be split into 3 groups as well then so can the entire number.
You can convince yourself that this works for larger numbers by using the same thinking and that the same argument holds for the divisibilty by 9 rule.

Re: Divisibility Tricks
by Xyro
on May 26, 2004

to be divisible by 6 the number needs to be even, and 1521893673 isn't even.


Re: Divisibility Tricks
by jgomez53
on Feb 19, 2005
Divisibility by others numbers.

By 13: Multiply the last digit by 4. Add this answer from the remaining digits. Is this number evenly divisible by 13? If it is, then your original number is evenly divisible by 13. Try 221, the last digit, multiplied by 4 = 4. And , the remaining digits 22, plus 4 = 26. The last time I checked, 26 is evenly divisible by 13, and thus, so is 221!

By 19: Multiply the last digit by 2. Add this answer from the remaining digits. Is this number evenly divisible by 19? If it is, then your original number is evenly divisible by 19. Try 304, the last digit, multiplied by 2 = 8. And , the remaining digits 30, plus 8 = 38. The last time I checked, 38 is evenly divisible by 19, and thus, so is 304! If this is not clear, we can do 38 --> 3+8*2 = 19
Greetings from Spain

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